2x+1=3x^2+4x+5

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Solution for 2x+1=3x^2+4x+5 equation: 



2x+1=3x^2+4x+5

We move all terms to the left:

2x+1-(3x^2+4x+5)=0

We get rid of parentheses

-3x^2+2x-4x-5+1=0

We add all the numbers together, and all the variables

-3x^2-2x-4=0

a = -3; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·(-3)·(-4)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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